Should I use shared mutable variable update in Java 8 Streams

Regardless of whether you use parallel or sequential Stream, you shouldn't use forEach when your goal is to generate a List. Use map with collect:

List<String> list2 = 
    list2.stream()
         .map(item -> item.startsWith("A") ? item : "EMPTY")
         .collect(Collectors.toList());

Functionally speaking,for the simple cases they are almost the same, but generally speaking, there are some hidden differences:

  1. Lets start by quoting from Javadoc of forEach for iterable use-cases stating that:

performs the given action for each element of the Iterable until all elements have been processed or the action throws an exception.

and also we can iterate over a collection and perform a given action on each element – by just passing a class that implements the Consumer interface

void forEach(Consumer<? super T> action)

https://docs.oracle.com/javase/8/docs/api/java/lang/Iterable.html#forEach-java.util.function.Consumer-


  1. The order of Stream.forEach is random while Iterable.forEach is always executed in the iteration order of the Iterable.

  1. If Iterable.forEach is iterating over a synchronized collection, Iterable.forEach takes the collection's lock once and holds it across all the calls to the action method. The Stream.forEach call uses the collection's spliterator, which does not lock

  1. The action specified in Stream.forEach is required to be non-interfering while Iterable.forEach is allowed to set values in the underlying ArrayList without problems.

  1. In Java, Iterators returned by Collection classes, e.g. ArrayList, HashSet, Vector, etc., are fail fast. This means that if you try to add() or remove() from the underlying data structure while iterating it, you get a ConcurrentModificationException.

https://docs.oracle.com/javase/8/docs/api/java/util/ArrayList.html#fail-fast


More Info:

  • What is the difference between .foreach and .stream().foreach?
  • What is difference between Collection.stream().forEach() and Collection.forEach()?