Using case for a range of numbers in Bash

I was looking for the simplest solution and found it difficult to use a case statement with a number range .

Finally i found a really simple solution for zsh :

  #!/usr/bin/zsh 

 case "${var}" in

 <0-5461>)

 printf "${var} is between 0 and 5461"

 ;;

 <5462-10922>)

printf "${var} is between 5462-10922"

 ;;

 esac

and for Bash :

  #!/bin/bash

 case $((   

(var >= 0 && var <= 5461)      * 1 +   

(var > 5462 && var  <= 10922)   * 2)) in   

(1) printf "${var} is between 0 and 5461";; 

(2) printf "${var} is between 5461 and 10922";; 

esac

Hope it helps someone .

Just for the pleasure of subverting case to do as you want, you can use $((...))

case 1 in
    $(($MovieRes<= 460)))echo "$MovieName,???";;
    $(($MovieRes<= 660)))echo "$MovieName,480p";;
    $(($MovieRes<= 890)))echo "$MovieName,720p";;
    $(($MovieRes<=1200)))echo "$MovieName,1080p";;
                       *)echo "$MovieName,DVD";;
esac >> moviefinal

The bash case statement doesn't understand number ranges. It understands shell patterns.

The following should work:

case $MovieRes in
    46[1-9]|4[7-9][0-9]|5[0-9][0-9]|6[0-5][0-9]|660) echo "$MovieName,480p" >> moviefinal ;;
    66[1-9]|6[7-9][0-9]|7[0-9][0-9]|8[0-8][0-9]|890) echo "$MovieName,720p" >> moviefinal ;;
    89[1-9]|9[0-9][0-9]|1[0-1][0-9][0-9]|1200)       echo "$MovieName,1080p" >> moviefinal ;;
    *)                                               echo "$MovieName,DVD" >> moviefinal ;;
esac

However, I'd recommend you use an if-else statement and compare number ranges as in the other answer. A case is not the right tool to solve this problem. This answer is for explanatory purposes only.

In bash, you can use the arithmetic expression: ((...))

if ((461<=X && X<=660))
then
    echo "480p"
elif ((661<=X && X<=890))
then
    echo "720p"
elif ((891<=X && X<=1200))
then
    echo "1080p"
else
    echo "DVD"
fi >> moviefinal