What is the simplest way to remove a trailing slash from each parameter?
This works for me: ${VAR%%+(/)}
As described here http://wiki.bash-hackers.org/syntax/pattern
May need to set the shell option extglob. I can't see it enabled for me but it still works
You can use the ${parameter%word}
expansion that is detailed here. Here is a simple test script that demonstrates the behavior:
#!/bin/bash
# Call this as:
# ./test.sh one/ two/ three/
#
# Output:
# one two three
echo ${@%/}
The accepted answer will trim ONE trailing slash.
One way to trim multiple trailing slashes is like this:
VALUE=/looks/like/a/path///
TRIMMED=$(echo $VALUE | sed 's:/*$::')
echo $VALUE $TRIMMED
Which outputs:
/looks/like/a/path/// /looks/like/a/path